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Archiver > GENIRE > 2003-03 > 1047639996


From: "Bob Builder" <>
Subject: Re: What is the meaning of the term "Scot-Irish"
Date: Fri, 14 Mar 2003 11:06:36 -0000
References: <NMLaa.10838$wJ1.1034032@newsread2.prod.itd.earthlink.net> <JbMaa.18415$EN3.149805@newsfep4-glfd.server.ntli.net> <1TMaa.210201$Zr%.52673@news01.bloor.is.net.cable.rogers.com> <a4dn6vgomas50urs2224akdlmbjj9bk5g4@4ax.com> <wsRaa.213443$Zr%.45044@news01.bloor.is.net.cable.rogers.com> <Ob7ba.32095$L1.6666@sccrnsc02> <WL8ba.220579$Zr%.75563@news01.bloor.is.net.cable.rogers.com> <V2nba.41841$L1.8170@sccrnsc02> <b4l5c5$u71$3@newsg2.svr.pol.co.uk> <1v6u6v8ta1laet4um7h3pi9h9m10020kn4@4ax.com> <3E6F4EC1.2090901@otenet.gr> <b4nmth$oka$1@newsg2.svr.pol.co.uk> <3E6FC194.8050005@otenet.gr> <b4phoh$4cj$1@news6.svr.pol.co.uk> <3e709dfd$0$4846$cc9e4d1f@news.dial.pipex.com> <b4q82c$2fn$1@newsg1.svr.pol.co.uk> <3E70CC46.DA65B7A8@alltel.net> <b4s495$t50$2@newsg2.svr.pol.co.uk> <3e71b108$0$29603$cc9e4d1f@news.dial.pipex.com>


"Mike Day" <> wrote in message
news:3e71b108$0$29603$...
>
> "Bob Builder" <> wrote in message
> news:b4s495$t50$2@newsg2.svr.pol.co.uk...
> >
> > "rick" <> wrote in message
> news:...
> > > Bob Builder wrote:
> > >
> > > > "Mike Day" <> wrote in message
> > > > news:3e709dfd$0$4846$...
> > > > >
> > > > > "Bob Builder" <> wrote in message
> > > > > news:b4phoh$4cj$1@news6.svr.pol.co.uk...
> > > > > >
> > > > > <snip>
> > > > > > > Genesis 5: 6
> > > > > > > And Seth lived an hundred and five years, and begat Enos;
> > > > > > > Genesis 5: 7
> > > > > > > And Seth lived after he begat Enos eight hundred and seven
> years, and
> > > > > > > begat sons and daughters;
> > > > > > > Genesis 6: 8
> > > > > > > And all the days of Seth were nine hundred and twelve years; and
> he
> > > > > died.
> > > > > > >
> > > > > >
> > > > > > Years were much shorter then because
> > > > > > the Earth was nearer the Sun.
> > > > > >
> > > > > > Bob
> > > > > >
> > > > > So Seth and co lived approx. 900 years. That is nominally of the
> order of
> > > > > 10 times more than a healthy individual in western society might
> live today.
> > > > > Let us assume that the actual years at that time were in fact
> shorter for
> > > > > the reason Bob states.
> > > > >
> > > > > Assuming the mass of both the sun and the earth are unchanged:
> > > > >
> > > > > 1. How much nearer to the sun would the earth have to be to provide
> an orbit
> > > > > of approximately 1/10th of the current duration?
> > > > >
> > > > > 2. How much warmer would it have been on the earth's surface as a
> > > > > consequence?
> > > > >
> > > >
> > > > Obviously warm enough to cause the great flood,
> > > > the like of which has never been seen since.
> > > >
> > > > Bob
> > >
> > > Hmm. So, the sun melted the ice caps, causing the flood? Which would
> imply that
> > > the earth was moving *towards* the sun, otherwise there wouldn't be any
> ice caps
> > > to melt. Now, we are moving away?
> > > Damn. I gotta pack. I *hate* moving....
> >
> > The maths is very complicated but when the earth was closer to the
> > sun it not just travelled a shorter distance but also travelled much
> faster.
> > The correllation between the length of the year and the surface
> temperature
> > of the planet is not at all straightforward.
> >
> > For the moment, I'm prepared to give the benefit of the doubt to the
> editor of the
> > Bible.
> >
> > Bob
> >
> According to Kepler's third law, the square of any planet's orbital
> (sidereal) period (P) is proportional to the cube of it's mean distance (R)
> from the Sun. That is to say that:
>
> P to the power 2 = (a constant c)*(R to the power 3)
>
> Let us use present earth years (Earth's sidereal period) as the unit of time
> (i.e. P=1), and for distance let us use Astronomical Units (AU) (the present
> mean distance of the earth from the sun) (i.e. R=1). In this case the
> constant c = 1 and therefore:
>
> (P to the power 2)=(R to the power 3)
>
> We are trying to determine what R should be if P is reduced to one tenth of
> earth's current orbital period. So if P=0.1, R must be equal to the cube
> root of P squared, or:
>
> R = P to the power 2/3
>
> Therefore R = 0.1 to the power 2/3
>
> so R ~ .215
>
> The present orbit of Mercury is at R = 0.39. Therefore Earth's orbit would
> be much closer to the Sun than Mercury is currently. To give some idea of
> how hot it would be at the Earth's surface, the daytime temperature on
> Mercury is approximately 700 degrees Kelvin or 427 degrees Celsius or 800
> degrees Fahrenheit. Whichever way you look at it that's hot!!
>

See, I told you the maths was complicated but I think you'll find
that Kepler's third law didn't exist in Biblical times

Bob





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